Talk:Early Fall 2018 Event/@comment-174.109.56.139-20180909031206/@comment-174.109.56.139-20180909035815

That was my thought initially too, but reading the current routing rules, 2CL/4DDDE meets the #2 start criteria of only DE/DD/CL/CT and "Meet ONE of the requrements" of DE+DE greater or equal to 4. It also meets the currently listed requirement to guarantee G by virtue of CL+CT greater or equal to 2. Where I run into a problem is G routing, I'd need to drop a DD in order to have three DEs for guaranteed F, making my route 2-G-F-I. If node E isn't a problem I can stick with 2DD and go 2-G-E-F-I.