Talk:Winter 2019 Event/@comment-24930367-20181231031053

> 9 surface radars

Absurd. Does "Easy" also need this amount?

...

Also this routing of T -> ZZ confuses me greatly. To go T -> ZZ, both options have:

- Amount of (F)BB(V) < 3

Yet straight below you have:

- If amount of (F)BB(V) + CV(B) < 3, random between V or ZZ

which implies even ZERO battleship could make you random to either V or ZZ?